CBSE Class 12 Physics 2023 Outside Delhi Set 1 Paper

© examsiri.com
Question : 28 of 35
 
Marks: +1, -0
A series CR circuit with R=200Ω and C=(50∕π) µF is connected across an ac source of peak voltage ε0,=100V and frequency v=50Hz. Calculate (a) impedance of the circuit (Z),(b) phase angle (ϕ), and (c) voltage across the resistor.
Solution:
(a) Given, R=200Ω,C=50πµF
Impedance: Z=R2+(1ωC)2
Or,
Z=(200)2+(12π×50×50π×10−6)2

Or,
Z=(200)2+(200)2
∴Z=2002
(b) Phase angle:
θ=tan−11ωCR
or, θ=tan−1(12π×50×50π×10−6×200)
or, θ=tan−11
∴ θ=45∘
(c) Voltage across resistor:
IRMS=εRMSZ
Or, IRMS=ε02Z
Or, IRMS =10022002
∴IRMS=14A
VR=IRMS ×R
Or, VR=14×200
∴VR=50V
© examsiri.com
Go to Question: