ICSE Class 10 Physics 2013 Solved Paper

Question : 44 of 70

Marks: +1, -0

A coin placed at the bottom of a beaker appears to be raised by

4.0 {\cm}

. If the refractive index of water is

4 \/ 3

, find the depth of the water in the beaker.

Solution:

Given : Shift

=4 {\cm}, µ=\;{4}/{3}

,
Real depth

=

?
We know that Shift

\;=\;\text " Real depth "\; (1-\;{1}/{{ }_a µ_m})

4\;=\;\text " Real depth "\; (1-\;{3}/{4})

4\;=\;\text " Real depth "\; × \;{1}/{4}

\;\text " Real depth "\;\;=\;{4 × 4}/{1}

\;=16 {\cm} .

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