ICSE Class 10 Physics 2016 Solved Paper

A battery of emf $12 {\V}$ and internal resistance $2 Ω$ is connected with two resistors $A$ and $B$ of resistance $4 Ω$ and $6 Ω$ respectively joined in series.

Find:

Question : 63 of 73

Marks: +1, -0

The potential difference across

6 Ω

Resistor.

Solution:

Potential difference across

6 Ω= {\IR}

=1 × 6=6 {\V}

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