ICSE Class 10 Physics 2023 Solved Paper

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A metre scale of weight 50gf can be balanced at 40cm mark without any weight suspended on it.
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Question : 52 of 76
 
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What minimum weight placed on this metre ruler can balance this ruler when it is pivoted at its centre?
Solution:

To balance the ruler with minimum weight of ' W ' gf, the weight must be suspended from 100cm mark.
In equilibrium,
Sum of anticlockwise moment = sum of clockwise moment.
⇒50×10gfcm=W×50gfcm
∴W=50050=10gf
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