ICSE Class X Math 2015 Solved Paper

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ABC is a right angled triangle with ∠ABC= 90∘.D is any point on AB and DE is perpendicular to AC. Prove that :
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Question : 47 of 52
 
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△ADE∼△ACB.
Solution:
To Prove : △ADE∼△ACB
(i) In △ADE and △ACB
(1) ∠A=∠A [common]
(2) ∠AED=∠ABC
=90∘ (given)
∴△ADE∼△ACB [AA axiom]
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