ICSE Class X Math 2015 Solved Paper

Question : 52 of 52

Marks: +1, -0

Construct a triangle

A B C

with

A B=5.5 {\cm}

A C=6 {\cm}

and

∠ B A C=105^{∘}

. Hence
(i) Construct the locus of points equidistant from

B A

and

B C

.
(ii) Construct the locus of points equidistant from

B

and

C

.
(iii) Mark the point which satisfies the above two loci as

P

. Measure and write the length of PC.

Solution:

Steps of Construction :
(i) Draw a line

{\AB}=5.5 {\cm}

.
(ii) With the help of the point

{\A}

, draw

∠ {\XAB}=105^{∘}

.
(iii) Taking radius

6 {\cm}

, cut

{\AC}=6 {\cm}

and join

{\C}

{\B}

.
(iv) Draw perpendicular bisector of

{\BC}

and angle of bisector

∠ {\CBA}

; both intersecting at

P

{\P}

is the required point.

P C=4.8 {\cm} \;\text ". "\;

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