What is \frac{ \sin ⁡\theta + 1}{\cos ⁡\theta } equal to?

Correct Answer is : cos⁡θ− sin⁡θ+1 sin⁡θ+cos⁡θ−1

\frac{ \sin ⁡\theta + \cos ⁡\theta −1}{ \sin ⁡\theta + \cos ⁡\theta + 1}

\frac{ \sin ⁡\theta + \cos ⁡\theta −1}{ \sin ⁡\theta + \cos ⁡\theta −1}

\frac{ \sin ⁡\theta −\cos ⁡\theta −1}{ \sin ⁡\theta + \cos ⁡\theta + 1}

\frac{\cos ⁡\theta − \sin ⁡\theta + 1}{ \sin ⁡\theta + \cos ⁡\theta −1}

Agniveer Vayu or IAF Group X 18 Jan 2023 Paper

Question : 43 of 70

Marks: +1, -0

What is ‌

sin‌⁡θ‌‌+‌1

cos‌⁡θ‌

equal to?

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