AIEEE 2003 Chemistry Solved Paper

Section: Chemistry

Question : 47 of 76

Marks: +1, -0

The rate law for a reaction between the substances A and B is given by Rate =k[A]n[B]m On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

[AIEEE 2003]

(m+n)
(n−m)
2(n−m)
‌
1
2(m+n)

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