AIEEE 2003 Math Solved Paper

Section: Mathematics

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Question : 29 of 66

Marks: +1, -0

The trigonometric equation sin‌−1x=2sin‌−1a has a solution for

[AIEEE 2003]

|a|≥‌
1
√2
‌
1
2
<|a|<‌
1
√2
all real values of a
|a|≤‌
1
√2

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