A nucleus with Z=92 emits the following in a sequence: \alpha, \beta^{-}, \beta^{-}, \alpha, \alpha, \alpha, \alpha, \alpha, \beta^{-}, \beta^{-}, \alpha, \beta^{+}, \beta^{+}, \alpha Then Z of the resulting nucleus is [AIEEE 2003]

AIEEE 2003 Physics Solved Paper

Section: Physics

Question : 66 of 74

Marks: +1, -0

A nucleus with Z=92 emits the following in a sequence:
α,β−,β−,α,α,α,α,α,β−,β−,α,β+,β+,α
Then Z of the resulting nucleus is

[AIEEE 2003]

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