AIEEE 2008 Solved Paper

Let m=0.50‌kg and M=1.0‌kg
Initial kinetic energy of the system when 1‌kg mass is at rest,
K.Ei=‌

1

2

mu2+‌

1

2

M(0)2
=‌

1

2

×0.5×2×2+0=1J
For collision, applying conservation of linear momentum
m×u=(m+M)×v
∴0.5×2=(0.5+1)×v⇒v=‌

2

3

m∕s
Final kinetic energy of the system is
K.Ef=‌

1

2

(m+M)v2
=‌

1

2

(0.5+1)×‌

2

3

×‌

2

3

=‌

1

3

J
∴ Energy loss during collision
=(1−‌

1

3

)J=0.67J