\int{ \sqrt { x - 1 } }/ { x \sqrt { x + 1 } } { dx } is equal to

Correct Answer is : ln|x+√x2−1|−sec−1x+C

\ln | x - \sqrt { x ^ { 2 } - 1 } | - \tan ^ { - 1 } x + C

\ln | x + \sqrt { x ^ { 2 } - 1 } | - \tan ^ { - 1 } x + C

\ln | x -\sqrt { x ^ { 2 } - 1 } | - \sec ^ { - 1 } x + C

\ln | x + \sqrt { x ^ { 2 } - 1 } | - \sec ^ { - 1 } x + C

AP and TS EAMCET Engineering Model Paper 11

Question : 71 of 160

Marks: +1, -0

∫

√x−1

x√x+1

dx is equal to

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