The latus rectum of a hyperbola is 9 / 2 and eccentricity is 5/ 4 . Its equation in standard form is:

Correct Answer is : 9x2−16y2=144

9 x ^ { 2 } - 16 y ^ { 2 } = 144

9 x ^ { 2 } - 16 y ^ { 2 } = 400

16 x ^ { 2 } - 9 y ^ { 2 } = 144

25 x ^ { 2 } - 16 y ^ { 2 } = 400

AP and TS EAMCET Engineering Model Paper 13

Question : 63 of 160

Marks: +1, -0

The latus rectum of a hyperbola is

and eccentricity is

. Its equation in standard form is:

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