AP and TS EAMCET Engineering Model Paper 14

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Question : 125 of 159

Marks: +1, -0

C6H5Z

KMnO4∕KOH

–––––––▶

A

H3O+

–––––––▶

C6H5COOH. Z cannot be

−CH3
−COCH3
−C(CH3)3
−CH2CH2CH2CH3

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