Exam Siri
Home
Exams
Banking Entrance Exams
CUET Exam Practice Tests
Defence Exams Practice Tests
Engineering Entrance Exams
Finance Entrance Exams
GATE Entrance Exams
Insurance Entrance Exams
International Entrance Exams
Joint Entrance Examinations
Law Entrance Exams
Management Entrance Exams
MCA Entrance Exams
Medical Entrance Exams
Other Entrance Exams
Police Entrance Exams
Public Service Commission
Railway Entrance Exams
Staff Selection Entrance Exams
State Government exams
Subjectwise Practice Tests
Teacher Eligibility Tests
State Eligibility Tests
UPSC Entrance Exams
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra Pradesh State Board Papers
Bihar State Board Papers
CBSE Board Papers
Gujarat State Board Papers
Haryana State Board Papers
ICSE Board Papers
Jammu & Kashmir State Board Papers
Karnataka State Board Papers
Kerala State Board Papers
Madhya Pradesh State Board Papers
Maharashtra State Board Papers
Odisha State Board Papers
Tamil Nadu State Board Papers
Telangana State Board Papers
Uttar Pradesh State Board Papers
English
Competitive English
CBSE
CBSE Board Papers
NCERT Books
NCERT Exemplar Books
NCERT Study Notes
CBSE Study Concepts
CBSE Class 10 Previous Paper Solutions
CBSE Class 12 Previous Paper Solutions
NCERT Book Class 11 Solutions
NCERT Book Class 12 Solutions
ICSE Class 10 Exams
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Privacy
Home
Back
AP and TS EAMCET Engineering Model Paper 16
Show Para
Hide Para
© examsiri.com
Question :
66 of 160
Marks:
+1
,
-0
Given that
|
2
a
x
1
y
1
2
b
x
2
y
2
2
c
x
3
y
3
|
=
abc
2
. Then area of the triangle whose vertices are
(
x
1
a
,
y
1
a
)
,
(
x
2
b
,
y
2
b
)
,
(
x
3
c
,
y
3
c
)
is
a
b
c
8
1
8
a
b
c
4
1
4
Validate
Solution:
|
2
a
x
1
y
1
2
b
x
2
y
2
2
c
x
3
y
3
|
=
abc
2
⇒
2
a
b
c
|
1
x
1
a
y
1
a
1
x
2
b
y
2
b
1
x
3
c
y
3
c
|
=
abc
2
⇒
|
1
x
1
a
y
1
a
1
x
2
b
y
2
b
1
x
3
c
y
3
c
|
=
1
4
But area of required triangle
=
1
2
|
1
x
1
a
y
1
a
1
x
2
b
y
2
b
1
x
3
c
y
3
c
|
=
1
2
×
1
4
=
1
8
© examsiri.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
Prev Question
Next Question