\int { \sec x }/ { ( \sec x + \tan x ) ^ { n } } d x , ( n ∊ z ^ { + } ) =

Correct Answer is : −1n( secx+tanx)n+c

{ 1 }/ { n ( { \sec x } + \tan x ) ^ { n } } + c

{ 1 } /{ ( n - 1 ) ( { \sec x } + \tan x ) ^ { n - 1 } } + c

{ - 1 } /{ n ( { \sec x } + \tan x ) ^ { n } } + c

{ - 1 }/ { ( n - 1 ) ( { \sec x } + \tan x ) ^ { n - 1 } } + c

AP and TS EAMCET Engineering Model Paper 5

Question : 72 of 160

Marks: +1, -0

∫

sec‌x

(sec‌x+tan‌x)n

dx,(n∊z+)=

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