AP and TS EAMCET Engineering Model Paper 8

∆WAB = P∆V = 10(2 −1) = 10 J
∆WBC = o (as V = const.)
From fist law of thermodynamics,
∆Q = ∆U + ∆W
But ∆V = 0 (Process ABCA is cyclic)
∆Q = ∆WAB + ∆WBC + ∆WCA
∆WCA = ∆Q − ∆WAB − ∆WBC
= 5 − 10 − 0 = − 5J