The equation for the stationary vibrations of a string of length 0.75 m fixed at both ends and vibrating is given by y = (0.2 \mm) \sin(4\\Pi x) \cos(1000 \\Pi\t), where x is in meters and t is in seconds. Then the string must be emitting its

Correct Answer is : third harmonic

AP and TS EAMCET Medical 2020 Model Paper 3

Question : 89 of 159

Marks: +1, -0

The equation for the stationary vibrations of a string of length 0.75 m fixed at both ends and vibrating is given by y=(0.2‌mm)‌sin(4Πx)‌cos(1000Πt), where x is in meters and t is in seconds. Then the string must be emitting its

fundamental frequency
second harmonic
third harmonic
fourth harmonic

Validate

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