AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

MxOy+H2→xM+yH2O
The number of moles of metal is calculated as
n‌metal ‌‌‌=‌

3.2

64

‌‌=0.05
Mass of oxygen is equal to 3.6−3.2=0.4
The number of moles of oxygen is calculated as:
n‌oxygen ‌‌‌=‌

0.4

16

‌‌=0.025
The ratio can be calculated as:
‌

n‌metal ‌

n‌oxygen ‌

‌‌=‌

0.05

0.025

‌‌=‌

2

1

Therefore, the formula of the oxide is M2O