If x ≠ -3/\sqrt2 , then ∫ x^2/{2x^2+6\sqrt2+9} dx =

Correct Answer is : 22√2[(√2x+3)−6log|√2x+3|−9√2x+3] + c

2/{2\sqrt2}[(\sqrt2x+3)-6 \log {|\sqrt2x+3|}-9/{\sqrt2x+3}] + c

2/{2\sqrt2}[\sqrt2x+3-6 \log {|(\sqrt2x+3)|}+9/{\sqrt2x+3}] + c

\sqrt2x + 3 - 6 log (\sqrt2x+3) + c

AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

If x ≠ −

√2

, then ∫

2x2+6√2+9

dx =

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