AP EAMCET Engineering 20 Apr 2019 Shift 2 Paper

The expression of kinetic energy for rotating disc is given as,
KE1=‌

1

2

mv12+‌

1

2

Iω2
KE1=‌

1

2

mv12+‌

1

2

(‌

mR2

2

)(‌

v1

R

)2
KE1=‌

3

4

mv12
The expression of the kinetic energy for the sliding disc is,
KE2=‌

1

2

mv22
Given condition, KE1=KE2
Substitute values.
‌

3

4

mv12=‌

1

2

mv22
‌

v12

v22

=‌

2

3

v1:v2=√2:√3