19g of a mixture containing NaHCO3 and Na2CO3 on complete heating liberated 1.12L of CO2 at STP. The weight of the remaining solid was 15.9g. What is the weight (in g ) of Na2CO3 in the mixture before heating?
Molecular weight of NaHCO3=23+1+12+48=84 Molecular weight ofNa2CO3=46+12+48=106 Hence, total weight =84+106=190 ∵ In 190g of a mixture, weight of Na2CO3 is =106 ∴ In 19g of a mixture weight of Na2CO3=