‘M’ kg of water ‘t ^0C is divided into two parts so that one part of mass ‘m’ kg when converted into ice at 0^0C would release enough heat to vapourize the other part, then m/M is equal to [ Specific heat of water =1\text{cal}g^{-1} ^0C^{-1} Latent heat of fusion of ice =80calg^{-1} Latent heat of steam=540\text{cal}g^{-1} ]

AP EAMCET Engineering 2016 Code C Paper

Section: Physics

Question : 109 of 160

Marks: +1, -0

‘M’ kg of water ‘t 0C is divided into two parts so that one part of mass ‘m’ kg when converted into ice at 00C would release enough heat to vapourize the other part, then

is equal to
[ Specific heat of water =1calg−1‌0C−1
Latent heat of fusion of ice =80calg−1
Latent heat of steam=540calg−1 ]

640−t
720−t
640
640+t
720
640−t
720

Validate

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