The solution of the differential equation (1+y^2)+(x-e^{\text{\tan}^{-1}y})\frac{dy}{dx}=0 is

Correct Answer is : 2xetan−1y=e2tan−1y+c

xe^{\text{\tan}^{-1}y}=\text{\tan}^{-1}y+c

xe^{2\text{\tan}^{-1}y}=e^{-\text{\tan}^{-1}y}+c

2xe^{\text{\tan}^{-1}y}=e^{2\text{\tan}^{-1}y}+c

x^2e^{\text{\tan}^{-1}y}=4e^{2\text{\tan}^{-1}y}+c

AP EAMCET Engineering 2016 Code C Paper

Section: Mathematics

Question : 53 of 160

Marks: +1, -0

The solution of the differential equation (1+y2)+(x−etan−1y)

=0 is

Go to Question:

Prev Question

Next Question