Two charged balls moving in the same direction with same velocity v are placed in an electric field. After some time, one ball moves with velocity v/ 2 at an angle of 60° with the initial direction and the other ball moves at right angles to the initial direction with a velocity v′. Then the value of v′ is

Correct Answer is : None of the above

AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

Section: Physics

Question : 105 of 160

Marks: +1, -0

Two charged balls moving in the same direction with same velocity v are placed in an electric field. After some time, one ball moves with velocity

at an angle of 60° with the initial direction and the other ball moves at right angles to the initial direction with a velocity v′. Then the value of v′ is

v
√2
v
√3
v
2
None of the above

Validate

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