AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

Section: Mathematics

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Question : 63 of 160

Marks: +1, -0

lim

n→∞

[62+122+182+...+(6n)2]2

[5+10+15+...+5n][23+43+63+....+8n3]

=

4
5
144
5
4
25
144
25

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