AP EAMCET Engineering 2018 Apr 23 Shift 2 Paper

Given, y=5‌sin(4t+

π

3

)
So, the angular velocity is, ω = 4
The time period is, T=

2π

ω

=

2π

4

=

π

2

s
The time is, t=

T

4

=

π

8

s
The expression of velocity is,
v=

dy

dt

v=

d

dt

[5‌sin(4t+

π

3

)]
v=20‌cos(4t+

π

3

)
The velocity at t=

π

8

s is,
v=20‌cos(4(

π

8

)+

π

3

)
v=−

20√3

2

ms−1
The kinetic energy of particle is calculated as,
K=

1

2

mv2
K=

1

2

(

2

1000

)(−

20√3

2

)2
K=0.3J