AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Physics

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Question : 108 of 160

Marks: +1, -0

In the given circuit, current I is independent of the resistance R6. Then

R1R2R5 = R3R4R6
1
R5
+
1
R6
=
1
R1+R2
+
1
R3+R4
R1R4 = R2R3
R1R3 = R2R4

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