AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Equation of line passing through the point of intersection of L1 and L2 is
L1+λL2=0
(2x+3y+6)+λ(3x−y−13)=0
(2+3λ)x+(3−λ)y+6−13λ=0
This is parallel to the line 3x−4y+5=0
On comparing the coefficient of two equations,

2+3λ

3

=

3−λ

−4

=

6−13λ

5

−8−12λ=9−3λ
λ=

17

9

Substitute the value of the λ.
(2−

51

9

)x+(3+

17

9

)y+6+

221

9

=0
−33x+44y+275=0
3x−4y−25=0