AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

The given equation of the circle is
x2+y2+6x+4y−12=0
The centre (-3,-2)
The radius =√9+4+12=5 The shortest distance between point P and the circle isAP=OP−OA
AP=√(−3−2)2+(−2+14)2−5
=13
AP=8
Length of tangent from point P is
=√22+(−14)2+6.2+4(−14)−12
=12
The required length is =√8+12=2√5