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Question : 62 of 160
Marks:
+1,
-0
Solution:
Given,
| √1+x‌sin‌x−√cos‌x |
| tan22x |
Solve the above expression,
=| √1+x‌sin‌x−√cos‌x |
| tan22x |
×| √1+x‌sin‌x+√cos‌x |
| √1+x‌sin‌x+√cos‌x |
=| 1+x‌sin‌x−cos‌x |
| tan22x |
×| 1 |
| √1+x‌sin‌x+√cos‌x |
=| (1−cos‌x)+x‌sin‌x |
| tan22x |
× Solve further,
=| 2sin2+2x‌sin‌‌cos‌ |
| tan22x |
× = Apply limits,
==
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