AP EAMCET Engineering 2018 Apr 24 Shift 1 Paper

Section: Mathematics

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Question : 73 of 160

Marks: +1, -0

∫

x8−9x2+18

x4−3x2+3

dx =

x5
4
+x3+6x2 + x
x5
5
+
x4
4
+ 6x + c
x5
5
+x3 + 6x + c
x5
5
−
x3
2
+6x2 + c

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