AP EAMCET Engineering 21 Sep 2020 Shift 1 Paper

The centre of the circle
x2+y2−3x−4y−1=0 is C(3/2,2), now as it is given that the required circle passes through the point C(3/2,2) and having centre (5,2), so radius of required circle is
∴ Equation of required circle is
(x−5)2+(y−2)2=(‌

7

2

)2
⇒4x2+4y2−40x−16y+67=0