AP EAMCET Engineering 21 Sep 2020 Shift 2 Paper

(b) Internal diameter for hose pipe,
d1=4cm,r1=‌

d

2

=‌

4

2

=2cm=2×10−2m
Speed of water through hose pipe, v1=1ms−1
Speed of water through nozzle, v2=4ms−1
Diameter, d2= ?
According to principle of continuity,
‌A1v1=A2v2
⇒‌πr12v1=πr22v2
⇒‌r22=‌

r12v1

v2

⇒r22=‌

(2×10−2)2×1

4

⇒‌r22=10−4
⇒‌r2=10−2m⇒r2=1cm
∴‌‌ Diameter of nozzle, ‌d2=2r2=2×1=2cm