AP EAMCET Engineering 22 Sep 2020 Shift 1 Paper

Section: Mathematics

Question : 73 of 160

Marks: +1, -0

The cartesian equation of a line is 2x−3 = 3y+1 = 5−6x. The vector equation of the line passing through the point (7,−5,0) and parallel to the given line is

→
r
= (5
^
i
−7
^
j
) + λ(3
^
i
+2
^
j
−
^
k
)
→
r
= (7
^
i
+5
^
j
) + λ(3
^
i
−2
^
j
+
^
k
)
→
r
= (7
^
i
−5
^
j
) + λ(3
^
i
+2
^
j
−
^
k
)
→
r
= (−5
^
i
+7
^
j
) + λ(−3
^
i
−2
^
j
−
^
k
)

Validate

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