AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

For vessel A,
The reaction of hydrogen peroxide is shown below,
2H2O2→2H2O+O2
The 10mL O2 is obtained by,
w=

2‌mol‌of‌H2‌O2×VH2O2

Vat‌NTP

Substitute the value in above we get,
w=

2×34×10

22400

=0.03gH2O2
For vessel B,
The solution of 30 mL O2 is obtained by,
w=

2‌mol‌of‌H2‌O2×VH2O2

Vat‌NTP

Substitute the value in above we get,
w=

2×34×30

22400

=0.09gH2O2
For vessel B,
The molarity is give as,
M=

n H2O2

Vsol

Here, the number of moles of H2O2 is n H2 O2 and the volumeoff the solution is Vsol
Substitute the value in above expression.
2=

x∕34

250∕1000

x=17g
Thus, the order of weight of H2O2 in vessel is C>B>A.