AP EAMCET Engineering 23 Apr 2019 Shift 1 Paper

Consider the diagram,The equation of sides is,
7x−y+3=0
x+y−3=0
The equation for the angle of bisector of above two is,

7x−y+3

√49+1

=±

x+y−3

√1+1

7x−y+3

√50

=±

x+y−3

√2

7x−y+3=5x+5y−15 or 7x−y+3=−5x−5y+15
2x−6y+12=0‌‌‌‌ or 12x+4y−12=0
This implies,
x−3y+6=0 or 3x+y−3=0
So,
slope =

1

3

, slope =−3( ‌integer)
Therefore, the required slope of third side is −3.