AP EAMCET Engineering 23 Sep 2020 Shift 1 Paper

Given that, radius, R=2m
Mass, m=8kg
Angular speed, ω=4rad/s
Moment of inertia of flywheel about an axis perpendicular to its plane and passing through its
centre, I=‌

mR2

2

=‌

8×(2)2

2

=16kg−m2
Therefore, kinetic energy of rotating fly wheel
KE=‌

1

2

Iω2=‌

1

2

×16×(4)2=128J