AP EAMCET Engineering 24 Apr 2017 Shift 1 Paper

When two cells of emfs E1‌and‌E2 and different internal resistances are connected in series with ail external load resistor, the current through the load is 5 A. If the polarity of cell of emf E2 is reversed then the current through the load is 2A. Then

E1

E2

=