\int(\sqrt{\tan x}+\sqrt{\cot x})\dx=

Correct Answer is : √2Tan−1(tanx−1√2tanx)+c

\sqrt2 \Tan^{-1}({\tan\x+1}/\sqrt{\tan x})+c

\sqrt2 \Tan^{-1}({\tan\x-1}/\sqrt{2tan x})+c

1/\sqrt2 \Tan^{-1}(\frac{\tan\x+1}{\sqrt2tan x})+c

1/\sqrt2 \Tan^{-1}(\sqrt{\tan\x}-1}/{\sqrt2tan x})+c

AP EAMCET Engineering 24 Apr 2017 Shift 1 Paper

Section: Mathematics

Question : 72 of 160

Marks: +1, -0

∫(√tan‌x+√cot‌x)‌dx=

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