AP EAPCET 05-Jul-2022 Shift 2 Paper

Initial frequency of oscillating pendulum,
f1=8‌Hz
We know that, frequency of oscillation of pendulum
f=‌

1

T

‌=‌

1

2π

√‌

g

l

⇒f∝‌

1

√l

⇒‌‌‌

f2

f1

‌=√‌

l1

l2

.....(i)
When the pendulum is clamped at its mid-point, then its length becomes half of initial length.
i.e
l2=‌

l

2

From Eq. (i), we get
‌

f2

f1

‌=√‌

l1

l1

=√2
⇒‌‌f2‌=√2f1=√2×8
‌=11.31‌Hz
‌=11.28‌Hz