AP EAPCET 07-Jul-2022 Shift 2 Paper

The given situation is shown below

Velocity of efflux through a hole below depth H of fluid,
v=√2gH
Volume flow rate of fluid from hole of area
a=V=av
V=a√2gH ...(i)
Here
V=2×10−3m3∕ s
a=5cm2=5×10−4m2
So from Eq.(i) , we get
2×10−3=5×10−4×√2×10×H
⇒H=

8

10

m=80‌cm