AP EAPCET 18th May 2023 Shift 2 Solved Paper

Section: Mathematics

Question : 52 of 160

Marks: +1, -0

Let C be the centre and A be one end of a diameter of the circle x2+y2−2x−4y−20=0. If P is a point on AC such that A divides CP in the ratio 2:3, then the locus of P is

x2+y2−2x−4y−205=0
2x2+2y2−4x−8y−405=0
x2+y2−2x−4y−450=0
4x2+4y2−8x−16y−605=0

Validate

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