AP EAPCET 18th May 2023 Shift 2 Solved Paper

Section: Mathematics

© examsiri.com

Question : 58 of 160

Marks: +1, -0

The equation of the pair of asymptotes of the hyperbola ‌

(x−3)2

3

−‌

(y−2)2

2

=1 is

2x2−3y2−12x+12y−6=0
2x2−3y2−12x+12y+8=0
2x2−3y2−12x+12y−8=0
2x2−3y2−12x+12y+6=0

Go to Question:

Prev Question

Next Question