AP EAPCET 20-Aug-2021 Shift 2 Paper

Given, nature of gas = Diatomic (at constant pressure)
As we know that,
Internal energy, U=nCVΔT ...(i)
Heat energy, Q=nCpΔT ...(ii)
where, n= number of mole
CV= specific heat at constant volume
Cp= specific heat at constant pressure
and Cp=CV+R
If f= degree of freedom, then
Cp=

f

2

+R=

5R

2

+R=

7R

2

Now, dividing Eq. (i) by Eq. (ii), we get
⇒

U

Q

=

nCVΔT

nCpΔT

=

CV

Cp

=

5R 2

7R 2

=

5

7