AP EAPCET 23 May 2025 Shift 1 Paper

A thin uniform rod of length L, and we need the radius of gyration k about an axis passing through its centre and perpendicular to its length.
Formulae:
Moment of inertia (M.I.) about the given axis for a uniform rod is:
I=‌

1

12

ML2
The radius of gyration k is related to the moment of inertia by
I=Mk2
Substituting:
‌Mk2=‌

1

12

ML2
‌k2=‌

L2

12

‌k=‌

L

√12