AP EAPCET 24-Aug-2021 Shift 2 Paper

Given that, moment of inertia, 1=1.2‌kg−m2
Initial angular velocity, ω0=0
Initial angular velocity, ω0=0
Angular accelcration, α=30 rad s−2
Final rotational kinetic energy, Kf=1800J
Let final angular velocity =ω
Using, Kf=

1

2

Iω2
By substituting the values, we get
1800=

1

2

×1.2×ω2
⇒ω=10√30‌rad∕s
We know that, ω=ω0+αl
⇒10√30=0+30t
t=

√30

3

s