AP EAPCET 25-Aug-2021 Shift 2 Paper

Efficiency of Carnot engine, η=40%=0.4
Temperature of source T1=500K
Temperature of sin‌k‌T2=T
Desired efficiency, η=60%=0.6
Temperature of sink T2=T
Temperature of source T1= ?
For case 1 Efficiency, η=1−

T2

T1

=1−

T

500

⇒

4

10

=

500−T

500

⇒ 200=500−T
⇒ T=300K
For case 2 Efficiency, η2=1−

T2

T1

=1−

T

T1′

6

10

=1−

300

T1′

⇒

300

T1′

=1−

6

10

⇒

300

T1′

=

4

10

⇒

300

4

×10=Ti′
⇒T2′=750K