Indefinite Integration

Section: Mathematics

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Question : 48 of 89

Marks: +1, -0

∫e4x2+8x−4(x+1)‌cos(3x2+6x−4)‌dx=

[AP EAPCET 22 May 2024 Shift 2]

‌
e4x2+8x−4
25
[3‌sin‌(3x2+6x−4)−4‌cos(3x2+6x−4)]+c
‌
e4x2+8x−4
50
[4‌cos(3x2+6x−4)+3‌sin‌(3x2+6x−4)]+c
‌
e4x2+8x−4
25
[3‌cos(3x2+6x−4)+4‌sin‌(3x2+6x−4)]+c
‌
e4x2+8x−4
50
[4‌sin‌(3x2+6x−4)−3‌cos(3x2+6x−4)]+c

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