\int {1}/{ (1+x^2) \sqrt{x^2+2}} \dx= [AP EAPCET 22 May 2024 Shift 2]

Correct Answer is : −Tan−1√x2+2|x|+c

-{\Tan}^{-1} {\sqrt{x^2+2}}/{|x|}+c

{\Tan}^{-1} \sqrt{\frac{x^2+1}{x^2+2}}+c

-{\Tan}^{-1} \sqrt{\frac{x^2+2}{x^2+1}}+c

Indefinite Integration

Section: Mathematics

Question : 50 of 89

Marks: +1, -0

∫‌

(1+x2)√x2+2

‌dx=

[AP EAPCET 22 May 2024 Shift 2]

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